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function Outer(){
var a=10;
function Inner(){
var a = 20;
console.log(a);
}
Inner();
}
Outer();

In this codek I want the inner function to print the value of outer function's a(i.e 10). How do I achieve this?

orde
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Ananthula Snigdha
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1 Answers1

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When you delcare var a = 20; on the fourth line above, you're redeclaring a variable that is already in scope and assigning it a new value. So the new value is what you get. If you remove that declaration, the name a will refer to the variable declaration in the outer scope and you'll get 10.

Stephen Crosby
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  • Hi Stephen, I've tried it but it's still printer the variable in the inner scope. I've found that bind() will helps to resolve this problem but i'm unable to figure it out. – Ananthula Snigdha Dec 17 '18 at 06:14
  • You must not have tried the same thing I'm trying. Take a look at this example on jsbin where I commented out the inner variable declaration: https://jsbin.com/taneyoviro/edit?html,output – Stephen Crosby Dec 19 '18 at 19:10