How can i write this euqation in matlab ∆φ12 = [φ1 −φ2] (mod 2π)

Question

I know the values for φ1 and φ1 and have to find the ∆φ12. Background of the equation: We know that the relationship between the absolute phase is Φ and the wrapped phase φ = Φ (mod 2π) with 2π discontinuities. Here the modulus operator is to convert the phase to a range of [0, 2π). Taking the modulus operation on Eq.(7) will lead to ∆φ12 = [Φ1 −Φ2] (mod 2π) = [φ1 −φ2] (mod 2π). Thanks

"Modulus" means measure, and is another name for the magnitude, or absolute value, of a number. "Modulo" is the term you're looking for. — Cris Luengo, Dec 04 '18 at 00:04

score 1 · Accepted Answer · answered Dec 03 '18 at 23:58

1

A quick Google search for "matlab mod" would have given you the page for the mod function. Anyway, here's what you need:

dphi12 = mod(phi1 - phi2, 2*pi);

answered Dec 03 '18 at 23:58

Savithru

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How can i write this euqation in matlab ∆φ12 = [φ1 −φ2] (mod 2π)

1 Answers1