Why I receive an error using Insert method in tkinter Entry?

Question

my code is very simple, but I receive this error

Traceback (most recent call last): File "F:/Download/PY/Timer2.py", line 10, in e1.insert(0,"5") AttributeError: 'NoneType' object has no attribute 'insert'

import tkinter
from tkinter import *

root = tkinter.Tk()
root.title(string='prova')
root.configure(background='lightgray')
lbl_title = Label(root, padx=10, text="Timer", fg='black', bg='lightgray', font='Times 24', anchor='center').grid(row=0)
lbl_time = Label(root, font="Times 38", fg='black', bg='lightgray', width=8).grid(row=1)
e1 = Entry(root,font="Times 22", fg='black', bg='white', width=6).grid(row=2, column=0)
e1.insert(0,"5")
btn_start = Button(root, text='START', bg='black', fg='white', font='Times 24').grid(row=2, column=1)
root.mainloop()

Miraj50 · Accepted Answer · 2018-12-02T17:03:21.093

If you try to print the value of e1, you will realize that it is actually None. That's because you have used the grid() method just after you have defined the Entry widget and grid() returns None. So, you need to separate them. Here is the working code.

from tkinter import *

root = Tk()
root.title(string='prova')
root.configure(background='lightgray')
lbl_title = Label(root, padx=10, text="Timer", fg='black', bg='lightgray', font='Times 24', anchor='center').grid(row=0)
lbl_time = Label(root, font="Times 38", fg='black', bg='lightgray', width=8).grid(row=1)
e1 = Entry(root,font="Times 22", fg='black', bg='white', width=6) ##
e1.grid(row=2, column=0) ##
e1.insert(0,"5")
btn_start = Button(root, text='START', bg='black', fg='white', font='Times 24').grid(row=2, column=1)
root.mainloop()

Also, now you should realize that your other variables are also None. Here is the new correct code.

import tkinter as tk

root = tk.Tk()
root.title(string='prova')
root.configure(background='lightgray')
tk.Label(root, padx=10, text="Timer", fg='black', bg='lightgray', font='Times 24', anchor='center').grid(row=0)
tk.Label(root, font="Times 38", fg='black', bg='lightgray', width=8).grid(row=1)
e1 = tk.Entry(root,font="Times 22", fg='black', bg='white', width=6)
e1.grid(row=2, column=0)
e1.insert(0,"5")
tk.Button(root, text='START', bg='black', fg='white', font='Times 24').grid(row=2, column=1)
root.mainloop()

@patel No, it's not about any order. Its about separating them so that e1 variable actually points to a widget and is not `None`. — Miraj50, Dec 02 '18 at 18:02
do you mean the variable does not point to widget after grid or pack ? — patel, Dec 02 '18 at 18:26
@patel only if you use it together as return value of them is None. — Miraj50, Dec 02 '18 at 18:28

Why I receive an error using Insert method in tkinter Entry?

1 Answers1