php : function require_once() path does not work

Question

Hi I don't know which path should put into parameter in require_once()

I am working with 7.2.10-0.

I have a directory which is

ice_hockey > data > teams.php 
ice_hockey > view > top.php
ice_hockey > index.php

My teams.php is like this

<?php
require_once('../view/top.php');
?>

but It does not work. I was searching for the path, especially relative path to put as parameter in require_once. Whatever I did, it doesn't work..

If I am put teams.php in the ice_hockey folder.
It will be easy but I need that folder to make easy.

How can I do? What is my problem here?

Please be specific about exactly what isn't working. What are you seeing, what were you expecting? Errors? Logs? etc. — Jonnix, Nov 30 '18 at 14:11
Using relative paths in PHP is generally a bad idea. https://gist.github.com/DaveRandom/6830e379578a66e2c82593137e79d099 — Tiffany, Nov 30 '18 at 14:12
Possible duplicate of [include\_once, relative path in php](https://stackoverflow.com/questions/7835948/include-once-relative-path-in-php) — CD001, Nov 30 '18 at 14:16
@JonStirling I think directory that I put as a parameter is correct but, it makes error. I want to know why it doesnot work. — sk Jin, Dec 04 '18 at 13:48

Devon Bessemer · Accepted Answer · 2018-11-30T14:20:56.097

The current working directory is not guaranteed to be where the script is located. When you access index.php from the web server, your CWD is going to be ice_hockey, not ice_hockey/data.

The same would apply if you were running in the command line from the root directory and ran:

php ice_hockey/data/teams.php

The CWD would be the root directory, or where you executed the command from.

Use the magic constant __DIR__ to use the current script's directory.

require_once(__DIR__ . '/../view/top.php');

This will always point to the correct location relative to where teams.php is located.

php : function require_once() path does not work

1 Answers1