Technically what others are suggesting is correct: the "insert" operation executed in the "exception when others" block will actually insert a new row in the log table.
the problem is that such insert statement will be part of the same transaction of the main procedure and, since you had an error while executing it, you are very likely to rollback that transaction, and this will rollback also the insert in your log table
I suppose the problem you are facing is not that you aren't successfully logging the error message: it is that you are rolling it back immediately afterwards, along with all the other writes you did in the same transaction.
Oracle gives you a way of executing code in a SEPARATE transaction, by using "autonomous transaction" procedures.
you need to create such a procedure:
create or replace procedure Write_Error_log(
arg_error_code number,
arg_error_msg varchar2,
arg_error_backtrace varchar2) is
PRAGMA AUTONOMOUS_TRANSACTION;
begin
INSERT INTO error_msg (
error_msg_id,
error_code,
error_msg,
error_stack)
VALUES (
error_msg_id_seq.NEXTVAL,
arg_error_code,
arg_error_msg,
arg_error_backtrace);
commit; -- you have to commit or rollback always, before exiting a
-- pragma autonomous_transaction procedure
end;
What this procedure does is to write a new record in the log table using a totally separate and independent transaction: the data will stay in the log table even if you execute a roll back in your calling procedure. You can also use such a procedure to create a generic log (not only errors).
All you have to do now is to call the procedure above whenever you need to log something, so your code becomes:
DECLARE
v_errcode NUMBER;
v_errmsg VARCHAR2(1000);
BEGIN
--some other statements that may raise exception.
EXCEPTION WHEN OTHERS THEN
Write_Error_log(SQLCODE, SQLERRM, dbms_utility.format_error_backtrace);
END;
/
P.S: there might be some typos in my code: I can't test it right now since I can't reach an oracle server in this moment.