Mongo DB , how select all documents in match query?

Asked Nov 27 '18 at 14:59

Active Nov 29 '18 at 14:42

Viewed 373 times

FOR getting all documents, what I write instead of XXXX. I want to get all values without a criterion. I must use aggregate and match function. payload.sla.customer.externalId variable is string.

db.collection.aggregate ( [
    { "$match" :    {        
    "payload.sla.customer.externalId" : XXXX 
    }}  
    ])

collection sample example

{
"_id" : ObjectId("5b929a84aff3dc185627add1"),
"payload" : { 
    "sla" : { 
            "customer" : { 
            "externalId" : "140689900", 
            }
        }
    }
}

edited Nov 29 '18 at 14:42

asked Nov 27 '18 at 14:59

hasan p.

What is `all` equal to `all`? What does `payload.sla.customer.externalId` contain? – Ashh Nov 27 '18 at 16:28
all = all , it is test. ı updated question. payload.sla.customer.externalId contains string. ı want get all document with match function – hasan p. Nov 27 '18 at 16:38
If you want to return all the documents then you don't need to use `$match` stage. Run the query without any stage. Not sure why you want to do this. – Ashh Nov 27 '18 at 16:42
I'll take the outside parameter, if there is no parameter, ı need to get all documents. so it is necessary – hasan p. Nov 27 '18 at 16:46
Then put the if else condition outside the query. – Ashh Nov 27 '18 at 16:49
yeap, you know , how can ı get all document in match query – hasan p. Nov 27 '18 at 16:53
1

Still unclear to me what you are asking. – Ashh Nov 27 '18 at 18:24

Mongo DB , how select all documents in match query?

0 Answers0