Calling Sys.argv in Print Command in Python

Question

I am a beginner programmer and i can't get this. Trying to print Sys.argv. I have the PRINT command set in script which should call sys.argv.

how do i run : python test.py device1

what i have tried :

print ('please Check' + sys.argv[1]_config.txt )

Current Output :

please Check + sys.argv[1]+_config.txt

what i am looking for :

print " please check device1_config.txt

Any Idea how to do this?

In test.py , did you use `from __future__ import print_function` to use that python3.x style print function? — vahdet, Nov 20 '18 at 09:15

score 1 · Accepted Answer · answered Nov 20 '18 at 09:06

1

for a in range(len(sys.argv)):
    # print(a)
    if 'device' in sys.argv[a]:
        print('please check device1_config.txt ')

Or to include it as a variable:

for a in range(len(sys.argv)):
    # print(a)
    if 'device' in sys.argv[a]:
        dev = sys.argv[a]
        print('please check {}_config.txt '.format(dev))

answered Nov 20 '18 at 09:06

Jimmy Newsom

66
2

if i run python test.py device2 , will it print "please check device2_config.txt" ?? – Nirmal Gauda Nov 20 '18 at 09:34
i ran the second part , it didn't print anything...however it didnt give me error either... – Nirmal Gauda Nov 20 '18 at 09:40
is script is executable and do you have the shebang path at the top? example: #!/usr/bin/python or on windows #!python – Jimmy Newsom Nov 20 '18 at 09:48

Calling Sys.argv in Print Command in Python

1 Answers1