How can I sort an array of Strings by another array of Ints in Swift 4

Question

I'm using this code in the Playground as an example:

let videosUnsorted = ["C Video", "G Video", "L Video", "T Video", "S Video ", "P Video", "A Video", "Z Video", "R Video"]

let videosValues = [1, 2, 3, 4, 5, 6, 7, 8, 9]

let sorted = videosUnsorted.sorted(by: {$0.videosValues > $1.videosValues})
print(sorted)

but it's giving me this error:

Argument passed to call that takes no arguments

I tried the following but it's not what I'm trying to accomplish. It's only sorting by the elements in the same array:

let sorted = videosUnsorted.sorted(by: {$0.1 < $1.2})

$0 is a `String`, and it doesn't have a property `videosValues`. — ielyamani, Nov 14 '18 at 22:58
See [this question](https://stackoverflow.com/q/33589534/1630618) — vacawama, Nov 14 '18 at 22:59
What result do you expect after the sort is complete? Please [edit] your question (no comments) with the exact results you want. — rmaddy, Nov 14 '18 at 23:02

score 1 · Answer 1 · answered Nov 14 '18 at 23:10

The easiest way is to use zip() like this:

zip(videosUnsorted, videosValues).sorted(by: { $0.1 < $1.1 }).map { $0.0 }

This combines the 2 arrays into the type [(String, Int)] you then sort by the Int values and use map() to get back out just the sorted [String].

How can I sort an array of Strings by another array of Ints in Swift 4

1 Answers1