What does %prec '.' mean here in yacc?

Question

notype_declarator:
      notype_declarator '(' parmlist_or_identifiers  %prec '.'
        { $$ = build_nt (CALL_EXPR, $1, $3, NULL_TREE); }

Anyone familiar with yacc rules?

score 10 · Accepted Answer · edited Aug 17 '18 at 07:39

10

It declares that the construct has the same precedence as the '.' operator, which have been specified earlier.

edited Aug 17 '18 at 07:39

cnexans

answered Mar 16 '11 at 19:16

geekosaur

2

Which symbol do you refer to by `that construct`? – assem Mar 16 '11 at 19:19
4

The whole expression before the `%prec`, actually. It's telling `yacc` how to disambiguate that branch of the parse tree relative to other similar branches. – geekosaur Mar 16 '11 at 19:25

score 0 · Answer 2 · answered Oct 27 '15 at 06:13

0

yacc program for showing error for 1) redeclaration of variable 2) Assignment expression error 3) operator missing

answered Oct 27 '15 at 06:13

Praniti Deshmukh

2 Answers2