A bash loop to echo all possible ASCII characters

Question

I know how to print all letters

{a..z} and {A..Z} and {0..9}

But is there a way to print all possible ASCII Characters via a bash loop?

Answer 1

If it is okay to use awk:

awk 'BEGIN{for (i=32;i<127;i++) printf("%c", i)}'

Or using printf:

for((i=32;i<127;i++)) do printf "\x$(printf %x $i)"; done

Answer 2

You don't need a loop

echo -e \\x{0..7}{{0..9},{A..F}}

It prints all chars from 0 to 127.

Answer 3

use this:

for ((i=32;i<127;i++)) do printf "\\$(printf %03o "$i")"; done;printf "\n"