Regular expression for sentences

Question

My regular expression works well when there is a space after the dot.

$str = 'Fry me a Beaver. Fry me a Beaver! Fry me a Beaver? Fry me Beaver no. 4?! Fry me many Beavers... End';

$sentences = preg_split('/(?<=[.?!])\s+(?=[a-z])/i', $str);

But I need it to work as well, when there is a \n after the dot.

$str = 'Fry me a Beaver. Fry me a Beaver!\nFry me a Beaver? Fry me Beaver no. 4?! Fry me many Beavers... End';

I can't add a \n to the regular.

You should try adding the multiline option via `/m` so `/(?<=[.?!])\s+(?=[a-z])/mi` might work. — MonkeyZeus, Nov 08 '18 at 20:21
`\n` in single quotes is a literal `\n` in PHP. Do you really have the above string? Demo https://3v4l.org/0AiLb — user3783243, Nov 08 '18 at 20:22
user3783243 has a point, are you sure you do not need the regex to work with `$str = "Fry me a Beaver. Fry me a Beaver!\nFry me a Beaver? Fry me Beaver no. 4?! Fry me many Beavers... End";`? — Wiktor Stribiżew, Nov 08 '18 at 20:25

score -1 · Accepted Answer · answered Nov 08 '18 at 20:23

-1

You can simply add an \\n, chained to your \s with an OR (|):
/(?<=[.?!])\s+|\\n+(?=[a-z])/i

This can be seen working here.

answered Nov 08 '18 at 20:23

Obsidian Age

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At the risk of sounding silly; would `\s+|(\\r\\n)+|\\r+|\\n+` be appropriate? – MonkeyZeus Nov 08 '18 at 20:25
`/(?<=[.?!])\s+|\\n+(?=[a-z])/i` is a corrupt pattern and won't do what is required. – Wiktor Stribiżew Nov 08 '18 at 20:26
It depends on *exactly* what OP is trying to target. For example, the `(?=[a-z])` will cause problems with the string `no. 4`. But it may matter what comes after the space. – Obsidian Age Nov 08 '18 at 20:26
Didn't you want to group that pipe `(\s+|\\n+)`? – revo Nov 08 '18 at 20:35

Regular expression for sentences

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