4

I'm catching an error with code: "links/failure"

const link = new firebase.links.DynamicLink(
      "LINK",
      "firebaseDomainLink"
    ).android
      .setPackageName("packagename")
      .ios.setBundleId("bundleID");
    firebase
      .links()
      .createShortDynamicLink(link, 'UNGUESSABLE')
      .then(url => {
        console.log(url)
      })
      .catch(err => {
        console.warn(err);
      });

However when using "createDynamicLink" I am able to get the long dynamic link as the return.

Tested with Android Platform

Picture of Yellow error box

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0 Answers0