python stopwatch in IF ELSE

Question

I try to insert stopwatch in my python code. Code read data from API, and if is value bigger then "3" switch relay to ON ( raspberry Pi3 ). This is read every XXX minutes. I want print time how long it's relay on or off.

while True:
    ts = time.time()
    st = datetime.datetime.fromtimestamp(ts).strftime('%H:%M:%S') 
    .
    . 
    .
    .
    .
    .
    if highest > 3:
        print("RELAY ON")
        print st
        print # time how long it's on
        GPIO.setmode(GPIO.BOARD)
        GPIO.setup(7, GPIO.OUT)

    else:
        print("RELAY OFF")
        print st
        print # time how long it's off
        GPIO.cleanup()

    time.sleep(60)

I try with this code, but I do not know where to insert it.

import time

start = time.time()
time.sleep(10)
end = time.time()

total = end-start
print total

Thankyou for help!

When you get to a resolution, please remember to up-vote useful things and accept your favourite answer (even if you have to write it yourself), so Stack Overflow can properly archive the question. — Prune, Nov 02 '18 at 20:46

Prune · Accepted Answer · 2018-11-02T20:14:59.923

Let's look only at the timing logic. When you turn the relay on, you mark that start time. The "time on" measurement continues until you turn the relay off. Then the "time off" timer starts, continuing until you turn it on again.

I suspect that you're a little confused because the start and stop events are in different code blocks. First, let's measure the "relay on" time. I'll make a flag relay_is_on to notice when the relay state changes. When the state changes, we'll take action: print the status change, reset the flag, and mark the start or stop time.

relay_is_on = False

while True:

    if highest > 3:
        if not relay_is_on:
            # Relay is just turning on;
            #   process changes
            print("RELAY ON")
            relay_is_on = True
            relay_on_start = time.time()

    else:
        if relay_is_on:
            # Relay is just turning off;
            #   process changes
            print("RELAY OFF")
            relay_is_on = False
            relay_on_end = time.time()
            relay_on_interval = relay_on_end - relay_on_start

From here, you can do whatever you need to accumulate or report the relay-on intervals. Also, if you need to similarly handle relay-off times, you simply add a few lines in the converse logic.

Can you continue from here?

First thankyou for help....I undertand you, but i want all the time print how long is relay ON, not only at the end - when switch. I want print, "relay ON - 10min", "relay ON - 20min" relay ON - 30min. And then OFF 10,20,30min. Every time when code loop adds extra time - IF true, or simple when is reley ON start stopwatch and show time of stopwatch in print or in my case in lcd display.... — McDam, Nov 02 '18 at 18:46
I showed you how to access and compute the amount of time on in your requested "stopwatch" fashion. You need only to move that code into your first ("true") block of the if, where you can check it every minute and print when you want. Exactly where are you stuck with implementing that logic? — Prune, Nov 02 '18 at 20:18

python stopwatch in IF ELSE

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