Convert list comprehension to for loop

Question

On this Huffman code, I found the below code.

heap = [[wt, [sym, ""]] for sym, wt in symb2freq.items()]

Is that possible to convert this kind of list compression into a for-loop?

`heap = [] for sym, wt in symb2freq.items(): heap.append([wt, [sym, ""]])` — Omkar Neogi, Oct 30 '18 at 15:55

score 0 · Accepted Answer · answered Oct 30 '18 at 15:58

0

Yes, you can:

heap = []
for sym, wt in symb2freq.items():
    heap.append([wt, [sym, ""]])

answered Oct 30 '18 at 15:58

N Chauhan

@N Chauhan append takes one argument, right? – Matthew Oct 30 '18 at 16:02
Yep. It adds the item given to the end of the list. – N Chauhan Oct 30 '18 at 16:03
Perfect, I got it. – Matthew Oct 30 '18 at 16:05

score -1 · Answer 2 · answered Oct 30 '18 at 15:56

-1

This works for me

heap = [[wt, [sym, ""]] for sym, wt in enumerate(symb2freq.items())]

answered Oct 30 '18 at 15:56

Jose Garcia

This doesn't give the same result and is still a list comprehension... – DavidG Oct 30 '18 at 15:58

2 Answers2