Ecplise say to me that I've an error in the web.xml page but I can't find it. This is the web.xml page
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
id="WebApp_ID" version="3.0">
<display-name>UnogasApp</display-name>
<filter-mapping>
<filter-name>jdbcFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<filter-mapping>
<filter-name>cookieFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<welcome-file-list>
<welcome-file>home</welcome-file>
<welcome-file>index.html</welcome-file>
<welcome-file>index.htm</welcome-file>
<welcome-file>index.jsp</welcome-file>
<welcome-file>default.html</welcome-file>
<welcome-file>default.htm</welcome-file>
<welcome-file>default.jsp</welcome-file>
</welcome-file-list>
</web-app>
When I try to run the code this is the error that occur: HTTP Status 404 – Not Found WEB-INF/views/homeView.jsp The origin server did not find a current representation for the target resource or is not willing to disclose that one exists. I think because the servlet can't find the home String in the welcome-file. thanks
I add the servlet class
@WebServlet(urlPatterns = { "/home"})
public class HomeServlet extends HttpServlet {
private static final long serialVersionUID = 1L;
public HomeServlet() {
super();
}
@Override
protected void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
// Forward to /WEB-INF/views/homeView.jsp
// (Users can not access directly into JSP pages placed in WEB-INF)
RequestDispatcher dispatcher = this.getServletContext().getRequestDispatcher("/WEB-INF/views/homeView.jsp");
dispatcher.forward(request, response);
}
@Override
protected void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
doGet(request, response);
}
}