Equivalent python code for curl command for https call

Question

I have a curl command that works and gives me back the JSON. Curl command:

    curl -sS -k -L -H "Authorization: bearer <token>" -X GET https://IP:PORT/api/v1/namespaces

I tried with requestsand pycurl modules which I found in the other posts but no luck.

Can anyone help me with finding the equivalent in python???

score 1 · Accepted Answer · answered Oct 16 '18 at 20:54

We can do this with requests like this:

import requests
header = {'Authorization': 'bearer <token>'}
resp = requests.get("https://IP:PORT/api/v1/namespaces", 
    headers = header, 
    verify=False)
print(resp.status_code)
print(resp.text)

The -H switch behaviour is replicated by sending a header
The -L switch behaviour is replicated by specifying verify=False
The -sS and -k are about the behaviour of curl and not relevant here
The -X GET is replicated by using requests.get()

Thanks, it works, the token I had was also not correct. Thanks again. — Mohammed, Oct 16 '18 at 21:06

Equivalent python code for curl command for https call

1 Answers1