so I've been given an assignment in which I'm supposed to find the index of the max and min values in a user-created 10 digit array in MIPS assembly language. I've been able to find the max value but I'm having trouble finding the min value. I figured it should be a simple solution once I find the max value but I was wrong.
Here is what i have to find the max value:
deleteMax:
# $s7 is the register where the address of the array is stored
# $s0 is the register where the array size is stored
# Clear out unimportant registers
addi $s1, $zero, 0
addi $t0, $zero, 0
addi $s3, $zero, 0
addi $s4, $zero, 0
addi $t6, $zero, 0
addi $t7, $zero, 0
addi $t0, $zero, 0 # Address of first element in bytes
li $t3, -1 # Max index
li $s2, 0 # Max value
li $t1, 0 # Counter
loop:
sll $s1, $t1, 2
add $s1, $s1, $s7
lw $s3, 0($s1) # Load the first element into $s3
li $v0, 1
move $a0, $s3
syscall
slt $t2, $s3, $s2 # If $s3 < $s2, $t2 = 1, if $s3 >= $s2, $t2 = 0
bne $t2, $zero, find_max
ori $s2, $s3, 0 # Updates the maximum value
ori $t3, $t1, 0 # Updates the maximum value index
find_max:
addi $t1, $t1,1 # Increase the counter
bne $t1, $s0, loop # if the counter hasn't reached the end, go
back to the loop
j print_max
This does what I want: Find the max and it's index. However when I try switching these 2 lines of codes:
slt $t2, $s3, $s2 # If $s3 < $s2, $t2 = 1, if $s3 >= $s2, $t2 = 0
bne $t2, $zero, find_max
to lets say:
slt $t2, $s3, $s2 # If $s3 < $s2, $t2 = 1, if $s3 >= $s2, $t2 = 0
bne $t2, 1, find_max
The min value comes out to 0?
I'm not sure why this is happening and unsure what I can do for my current situation to find the min value.
I hope I've explained myself and my code + comments have explained the situation enough. Im more than happy to answer any more confusion you guys may have.