I have a regex file that I am reading in and compiling. The issue I am having is the regex will sometimes leading \.
Z\\d*\\.file_\\.?
instead of
Z\d*\.file_\.?
It sometimes matching but others not.
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Jean-François Fabre
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user3525290
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[mcve] please. it's unclear what your inputs are – Jean-François Fabre Oct 08 '18 at 18:50
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Maybe another dupe of [Why do backslashes appear twice?](https://stackoverflow.com/questions/24085680/why-do-backslashes-appear-twice) – Wiktor Stribiżew Oct 08 '18 at 18:54
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We'll know when OP has edited – Jean-François Fabre Oct 08 '18 at 18:54
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Possible duplicate of [Why do backslashes appear twice?](https://stackoverflow.com/questions/24085680/why-do-backslashes-appear-twice) – Jean-François Fabre Oct 08 '18 at 18:55
2 Answers
1
Most likely it does not match when you use raw string and double backslash.
s = "ABC 23"
re.findall('\d+',s)
['23']
re.findall(r'\d+',s)
['23']
re.findall('\\d+',s)
['23']
re.findall(r'\\d+',s)
[]
LetzerWille
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I don't know if that is what you want but if you read documentation of regular expression operations
It says :
"Regular expressions use the backslash character ('\') to indicate special forms or to allow special characters to be used without invoking their special meaning"
And also :
"The solution is to use Python’s raw string notation for regular expression patterns; backslashes are not handled in any special way in a string literal prefixed with 'r'"
Example:
regex= re.compile(r'string')
tolis
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