Kotlin: How to check variable with lateinit property is initialized or not

Question

I have a variable that is declared like

private lateinit var apiDisposable: Disposable

and then in onPause() method, I am doing

override fun onPause() {
    super.onPause()
    if (!apiDisposable.isDisposed)
        apiDisposable.dispose()
}

But I get this

kotlin.UninitializedPropertyAccessException: lateinit property apiDisposable has not been initialized

Can anyone tell me how could I check if this variable is initialized or not? Is there any method like isInitialised()

Any help would be appreciated

score 16 · Answer 1 · answered Oct 05 '18 at 10:52

16

if(::apiDisposable.isInitialized)

will solve your problem.

In general,

::<lateinit variable name>.isInitialized is used to check if it has been initialized.

answered Oct 05 '18 at 10:52

Rahul

2

What is this variable was in a companion object? – IgorGanapolsky May 29 '20 at 19:12

score 16 · Accepted Answer · answered Oct 05 '18 at 10:54

Declare your property as a simple property of a nullable type:

private var apiDisposable: Disposable? = null

Call the method using the safe call notation:

override fun onPause() {
    super.onPause()
    apiDisposable?.dispose()
}

lateinit is reserved for variables that are guaranteed to be initialized, if this is not your case - don't use it.

2 Answers2