How can I access a class field by its name in racket?

Question

I can access a class field by defining a method so (send joe get-name) will return me Joe. But can I get the same behavior without adding a method and just by calling a field, like this: (send joe name)?

#lang racket

(define person%
  (class object%
    (init-field name)
    (super-new)
    (define/public (get-name) name) ))

(define joe (new person% [name 'Joe]))

I know I'm not answering your question at all, but: are you sure you need classes, here? Structs are a lot simpler and this question has a simple answer in that domain. — John Clements, Oct 02 '18 at 17:11

score 1 · Accepted Answer · edited Oct 10 '18 at 06:36

1

I think you're looking for get-field.

Example of usage: (get-field name joe)

Let me know if I've misunderstood your question.

edited Oct 10 '18 at 06:36

Aliaksandr Sushkevich

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answered Oct 04 '18 at 15:52

John Clements

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Could you please provide an example of using it? – Aliaksandr Sushkevich Oct 04 '18 at 15:57
have you tried it, or read the documentation? Stack overflow is a "proof-of-work" site, where you show what you've tried, and *then* we do more work for you :). – John Clements Oct 08 '18 at 00:56
1

Wouldn't ask you if I didn't. Probably I didn't use it correctly the first time, so it didn't work for me. Now it works, gonna add it to your answer. – Aliaksandr Sushkevich Oct 10 '18 at 06:34

How can I access a class field by its name in racket?

1 Answers1