Upload images for an event using Cloudinary API

Question

Below is my API endpoint for creating an event in my application. I'm also using Cloudinary API for uploading my images and storing the returned URL into my database.

app.post('/event', (req, res) => {
    try {
        if (req.body.images.length > 0) {
           // Creating new Event instance
            const event = new Event({
                title: req.body.title,
                images: [],
            });

           // Looping over every image coming in the request object from frontend
            req.body.images.forEach((img) => {
                const base64Data = img.content.split(',')[1];

            // Writing the images in upload folder for time being 
                fs.writeFileSync(`./uploads/${img.filename}`, base64Data, 'base64', (err) => {
                    if (err) {
                        throw err;
                    }
                });

              /* Now that image is saved in upload folder, Cloudnary picks 
             the image from upload folder and store it at their cloud space.*/
                cloudinary.uploader.upload(`./uploads/${img.filename}`, async (result) => {

                 // Cloudnary returns id & URL of the image which is pushed into the event.images array.
                    event.images.push({
                        id: result.public_id,
                        url: result.secure_url
                    });

                 // Once image is pushed into the array, I'm removing it from my server's upload folder using unlinkSync function
                    fs.unlinkSync(`./uploads/${img.filename}`);

       // When all the images are uploaded then I'm sending back the response
                    if (req.body.images.length === event.images.length) {
                        await event.save();
                        res.send({
                            event,
                            msg: 'Event created successfully'
                        });
                    }
                });
            });
        }
    } catch (e) {
        res.status(400).send(e);
    }
});

Now My question is how can I convert the above code into more efficient and short?