Python 2.7 Strict strip

Question

I have a string string = 'some.value:so this-can be:any.thing, even some.value: too'

I want to strip out the 'some.value:' on the left side.

My failed attempts:

>>> string.lstrip('some.value:')
' this-can be:any.thing, even some.value: too'
>>> string.replace('some.value:','')
'so this-can be:any.thing, even  too'
>>> string.split(':')[1]
'so this-can be'

Expected output: so this-can be:any.thing, even some.value: too

I think the closest to my answer is using the lstrip(). How can I tell the lstrip() to strip exactly the whole phrase?

[!] NOT using any library is preferred!

Note: There is a similar question but the answer is not applicable to me.

You want to strip it out on the right or left side, output and question do not match — Olivier Melançon, Sep 29 '18 at 17:08
Oh sorry, my mistake. I messed up the side haha :D. Just edited the question. I want to strip the _left_ side. — Programer Beginner, Sep 29 '18 at 17:09
@ProgrammerBeginner and does the target substring needs to be at the start or do you want to remove the first occurence wherever it is? — Olivier Melançon, Sep 29 '18 at 17:20
@OlivierMelançon, you guessed correctly that it has to be at the start. Thanks for the assistance. :) — Programer Beginner, Sep 29 '18 at 17:23

score 5 · Accepted Answer · answered Sep 29 '18 at 17:13

We check if the string to strip is a the start, and cut the string if it is the case:

def strip_from_start(strip, string):
    if string.startswith(strip):
        string = string[len(strip):]
    return string

print(strip_from_start('value:', 'value: xxx value: zzz'))
# xxx value: zzz

Python 2.7 Strict strip

1 Answers1