SQL Operator Precedence with braces

Question

I have a SQL query I do not quite understand regarding operator precedence:

SELECT
foo,
count(*)
FROM
A
JOIN (SELECT
  SUM(IF(bar = 2,1,0)) as bar_sum,
  SUM(IF(foo >= 1,1,0)) as foo,
  SUM(1) as sum_1
  FROM
  B
  ) as sums
GROUP BY
id,
bar_sum,
foo,
sum_1
ON A.id = B.id

does the GROUP BY from outer brace really apply to the inner one? Note, I need to port this SQL from Hive to Spark scala Dataframe API so I really need to get operator precedence right. From What is the execution sequence of Group By, Having and Where clause in SQL Server? it looks like in general this is true, but I did not find any documentation regarding the ().

score 1 · Accepted Answer · answered Sep 29 '18 at 07:58

This query looks incorrect (there is missing ON clause)

SELECT foo,count(*)
FROM A
JOIN (SELECT SUM(IF(bar = 2,1,0)) as bar_sum,
             SUM(IF(foo >= 1,1,0)) as foo,
             SUM(1) as sum_1
      FROM   B) as sums  -- should be `ON`
GROUP BY id, bar_sum, foo, sum_1;
        -- looks like grouping by sum_1, bar_sum is superflous

The GROUP BY is applied only to outer query. Please note that inner query will return single row.

SELECT SUM(IF(bar = 2,1,0)) as bar_sum,
       SUM(IF(foo >= 1,1,0)) as foo,
       SUM(1) as sum_1
FROM   B
-- single row

Then you join single row to table A and get as many rows as distinct (id,foo) values.

SQL Operator Precedence with braces

1 Answers1