compress list of files and directories with brotli

Question

I'd like to use brotli to compress a list of files and directories. I'm able to do this with zip running

zip -r  archive.zip *

and I'm looking for a similar command with brotli. I've tried

tar -cf archive.gz * && \
brotli -n -q 11 -o archive.zip archive.gz

but after decompression the zip doesn't have the same structure than with zip.

score 8 · Accepted Answer · answered May 04 '19 at 15:25

Your second command is actually right. Brotli, like Gzip/Bzip2/etc can only compress a single file.

What you must do is first package all of your files in a tarball:

tar -cvf output.tar /path/to/dir

And then compress the resulting tarball with Brotli:

brotli -j -Z output.tar

Which should leave you with a output.tar.br file (similar to *.tar.gz gzipped tarballs).

score 1 · Answer 2 · answered Jul 29 '23 at 13:35

Either of these commands will work to create a brotli compressed tar file without an intermediate tar file:

Directly using tar with the option --use-compress-program

tar -cvf test-output.tar.br --use-compress-program="brotli -Z" ./my_data_to_compress

Piping to brotli

tar --create --verbose ./my_data_to_compress | brotli --output=compressed_files.tar.br

score 0 · Answer 3 · answered Oct 31 '18 at 05:30

0

Have you tried Brotli-cli?

This comes with a lot of options to get files compressed using Brotli

answered Oct 31 '18 at 05:30

alchemist95

score -1 · Answer 4 · answered Mar 25 '19 at 19:43

-1

you can try creating a .tar file instead of .gz

answered Mar 25 '19 at 19:43

Please elaborate, why does that help? – JJJ Mar 25 '19 at 20:01
I thought he was trying to compress an already compressed file (gzip), which won't work.. but now I realized he's only naming as .gz (missing z parameter), so it's just a tarball .gz suffixed.. should work – Mateus Velleda Vellar Mar 25 '19 at 20:57

4 Answers4