Find the url of uploaded file, firebase storage + python

Question

I was wondering how could I get the url from the file I am uploading to the firebase storage? Here is my code:

    import firebase_admin
from firebase_admin import credentials, firestore, storage

cred=credentials.Certificate('/serviceAccountKey.json')
firebase_admin.initialize_app(cred, {
    'storageBucket': <my_bucket_name>
})
db = firestore.client()

bucket = storage.bucket()
blob = bucket.blob('image.jpg')
blob.upload_from_filename('/image.jpg')

#here I'd like to have url of file I uploaded
print(blob.<url>)

Thanks in advance.

You'll need to use `generate_signed_url`. Details can be found in the [reference doc](https://googlecloudplatform.github.io/google-cloud-python/latest/storage/blobs.html). — Jen Person, Sep 21 '18 at 22:26
I tried to use that, but it gives me link for example: https://storage.googleapis.com/project.appspot.com/image.jpg?GoogleAccessId=erviceaccount.com&Expires=86400&Signature=Yj2WtyANJO5nYCpr5vIaVdoVv0BqLreBYN6rSaCdXeSLq1mTv6m3QQ%2Fp31By6vf9RfYv2rWlg98acPAjr5zb73RfuDvhN7PcFQtbb23rpAYJClY6YJ0GAuc9%2Fvtispl%2BBvVcv7TdQSiwZM3ZhzMag%2FzqLFN0CgaFmPqDRwnm6FVXPhO%2FmHePiSD0SOu%2FGtIK4h7TUcf9wfsw4i75dP and what I want is link like this: https://firebasestorage.googleapis.com/v0/b/project.appspot.com/o/image.jpg?alt=media&token=d5809ce7-92a0-4e25-b3cf-fe684aac20ca — dolphin, Sep 22 '18 at 07:51
At this time, there is no way to get the link in the particular format that you're looking for, but it should work just the same. — Jen Person, Sep 24 '18 at 17:29

score 9 · Answer 1 · answered Aug 07 '20 at 12:04

9

You should use the following code:

blob.upload_from_filename(BLOB_PATH)
blob.make_public()
print(blob.public_url)

answered Aug 07 '20 at 12:04

Yan

347
3
3

Is there a reason why we need to specify the visibility of the blob if the storage already has rules? Thanks for that! – DsCpp Jun 02 '21 at 18:36

score 5 · Answer 2 · answered Feb 18 '19 at 14:50

You can get the public url with blob.public_url

Example code:

bucket = storage.bucket()
blob = bucket.blob(BLOB_PATH)
blob.upload_from_filename(FILE_PATH)
print(blob.public_url)

Documentation: https://googleapis.github.io/google-cloud-python/latest/storage/blobs.html#google.cloud.storage.blob.Blob.public_url

score 0 · Answer 3 · answered May 21 '20 at 06:23

0

image1 = face_recognition.load_image_file('99.jpg')
imageBlob_1 = bucket.blob('99.jpg')
imageBlob_1.upload_from_filename('99.jpg',content_type='image/jpeg')
URL_1 = imageBlob_1.public_url
response1 = requests.get(URL_1)

answered May 21 '20 at 06:23

Ahmed Agam

1

1

Please be more specific and explain what you want to achieve. – May 21 '20 at 06:38

score 0 · Answer 4 · answered Aug 18 '22 at 11:12

Change the Security RULE

Go to Firebase Security RULES inside the firebase storage
Change so that you upload files to the publically visible folder
Rest of the path should have auth restrictions

Sample Security Rule

Here all folders/ path expect NewFolder will have auth restriction.

rules_version = '2';
service firebase.storage {
  match /b/{bucket}/o {
     // Explicitly define rules for the 'NewFolder' pattern
    match /NewFolder/{allPaths}{
      allow  write: if request.auth != null; //Only auth users can write
      allow  read: if request.auth == null; //Publically readable
    }
    // This will be defined for everything else
    match /{allPaths=**} {
      allow  write: if request.auth != null; //Only auth users can write
      allow  read: if request.auth != null; //Only auth users can read
    }
  }
}

Find the url of uploaded file, firebase storage + python

4 Answers4

Change the Security RULE

Sample Security Rule