How to remove the first character if it's a comma using QRegExp?

Question

I have the following QRegExpValidator

QRegExpValidator doubleValidator = new QRegExpValidator(QRegExp("[-+]?[0-9]*[\\.,]?[0-9]+([eE][-+]?[0-9]+)?"));

It's supposed to be a Double numbers validator that accepts numbers, only one "e" sign, one comma OR dot and one + or - sign at the beggining of the string or after the "e" sign. It works for every case, except that it allows the string to start with a comma or dot. I tried to use [^\\.,] and variations and they did in fact work, but in this case, it would also allow to put two +- signs.

How can I make this to work?

A duplicate of [Regex match whole string](https://stackoverflow.com/questions/22432558/regex-match-whole-string) — Wiktor Stribiżew, Sep 12 '18 at 19:36
Yes, because you have `[0-9]*` there. What are the allowed types of numbers? If you do not allow `.0` like number use `"^[-+]?[0-9]+([.,][0-9]+)?([eE][-+]?[0-9]+)?$"` — Wiktor Stribiżew, Sep 13 '18 at 11:48

score 1 · Accepted Answer · answered Sep 13 '18 at 11:57

The [-+]?[0-9]*[.,]?[0-9]+([eE][-+]?[0-9]+)? pattern allows the , or . at the start because [-+]? and [0-9]* can match empty strings due to the ? (one or zero occurrences) and * (zero or more occurrences) quantifiers, and then [.,] matches a single occurrence of . or ,. Besides, if the method you are using does not anchor the pattern by default, you also need ^ and $ anchors around the pattern.

I suggest fixing that with

"^[-+]?[0-9]+([.,][0-9]+)?([eE][-+]?[0-9]+)?$"
 ^          ^^^^^^^^^^^^^^                  ^

Note you do not need to escape the dot inside a character class, [.] always matches a dot char only.

The [0-9]+([.,][0-9]+)? matches 1+ digits and then an optional sequence of a . or , followed with 1+ digits.

I'm using Qt; it always assumes the "^E$" on QRegExpValidator; I forgot to include that hehe. Thanks, buddy — Jorge Augusto Santos, Sep 13 '18 at 12:09

How to remove the first character if it's a comma using QRegExp?

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