SDL Window is transparent

Question

I'm learning SDL and tried to set up a window with a red background. Followed this code but got the result that is different from an expected one.

#include <stdio.h>
#include "SDL2/SDL.h"

int main(int argc, char const *argv[]) {

    if(SDL_Init(SDL_INIT_EVERYTHING) != 0) {
        SDL_Log(SDL_GetError());
        return -1;
    }

    SDL_Window* wnd = SDL_CreateWindow("Test", SDL_WINDOWPOS_UNDEFINED, SDL_WINDOWPOS_UNDEFINED, 300, 300, SDL_WINDOW_OPENGL);
    SDL_Renderer* renderer = SDL_CreateRenderer(wnd, 0, SDL_RENDERER_ACCELERATED);

    SDL_SetRenderDrawColor(renderer, 255, 255, 255 , 255);
    SDL_RenderClear(renderer);
    SDL_RenderPresent(renderer);

    SDL_Delay(6000);

    SDL_Quit();
    return 0;
}

SDL_SetRenderDrawColor(renderer, 255, 0, 0 , 255); try this to make it red — Simo, Sep 06 '18 at 15:34
You are creating a window for use with OpenGL but using the SDL APIs to draw to it... — John5342, Sep 07 '18 at 13:50

score 1 · Answer 1 · answered Sep 06 '18 at 15:42

1

Process the OS event queue via a SDL_WaitEvent()/SDL_PollEvent()/SDL_PumpEvents() loop instead of a big 'ole main-thread-blocking SDL_Delay().

answered Sep 06 '18 at 15:42

genpfault

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SDL Window is transparent

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