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Why does this only show the entry from data.csv one time? 

for i in `cat ~/Downloads/data.csv`
do
  echo $i $i
done

I have tried $i$i and the += operator and none of them seem to do what I would have expected. The goal is to create links from data.csv, which is a list of urls. So the output would ideally be 

<a href='$i'>$i</a>

I am using OSX.

Scott C Wilson
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    See [Bash FAQ 001](https://mywiki.wooledge.org/BashFAQ/001) for the correct way to iterate over the contents of a file. – chepner Sep 03 '18 at 12:14
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    Your CSV file probably has DOS line endings, so the carriage return in the variable value causes the second one to overwrite the first. – chepner Sep 03 '18 at 12:15
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    I'm sure you know that already, but it's maybe also a good hint for others: Caution on the output of `'$i'`. The single quotes have to be escaped or double quotes should be used to resolve variable correctly. – colidyre Sep 03 '18 at 12:17
  • @chepner Would you please make your comment into an answer? That was indeed the root cause of my trouble. Thanks to other posters though for improving my lazy `for` loop use. – Scott C Wilson Sep 03 '18 at 12:36

1 Answers1

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don't use bash for file content processing, awk is better suited for this.

$ awk '{print "<a href=\"" $0 "\">" $0 "</a>"}' file
karakfa
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