What's the easiest way to parse a JSON in Swift 4?

Question

I wrote the following function to do a GET request inside of my macOS app using Alamofire:

func getContent(room: String) -> String {
let scriptUrl = "https://klipped.in/api/\(room)"
Alamofire.request(scriptUrl).responseJSON { response in        
    if let json = response.result.value {
        print("\(json)") // serialized json response
    }
}
return "This should return the value of \"content\" in the json response"
}

I now want to parse the json in the most efficient way possible. I googled around ways to do this, but every solution I found seems overly complicated or doesn't run because of type problems.

Is there a simple way in Swift to access the values inside of a JSON without creating a Struct for every response? I'm thinking about something along the lines of:

get-json-value(json, "content")

That returns the string value of "content" inside of a json and null if it doesn't exist.

Its duplicate question. Try to use searching. Here is the answer. https://stackoverflow.com/a/50383222/8417137 — Alex Kolovatov, Sep 02 '18 at 16:46
If you are able to read the JSON the most efficient way is `Codable`. If not there is no easy way. — vadian, Sep 02 '18 at 17:26
Possible duplicate of [How to parse JSON using swift 4](https://stackoverflow.com/questions/50379653/how-to-parse-json-using-swift-4) — Ashley Mills, Sep 02 '18 at 17:31
I had already read the answer and found it strange that for parsing a JSON one had to write so many LOC. I was just asking if there are any libraries that made this process faster. — Ferruccio Balestreri, Sep 03 '18 at 08:16

Ferruccio Balestreri · Answer 1 · 2018-09-03T09:34:24.290

0

The easiest way to parse a JSON in Swift 4 when using Alamofire is by using

getRoomData = JSON as NSDictionary
str = getRoomData["content"] as String

See an example at: AlamoFire GET api request not working as expected

An even Better way is using the Swifty JSON library:

let json = JSON(responseData.result.value!)
let roomContent = json["content"].string

edited Sep 03 '18 at 09:34

answered Sep 03 '18 at 08:50

Ferruccio Balestreri

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What's the easiest way to parse a JSON in Swift 4?

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