imagecopyresampled in php -> destination file

Question

i'm using jCrop and CodeIgniter, trying to make an image uploader.
So i have my image folder and inside a temp folder.
I make the upload to my temp folder and then display the uploaded image with the cropper.
When i submit the form, i go to my php and use the code provided by jCrop:

$src = 'demo_files/flowers.jpg';
    $img_r = imagecreatefromjpeg($src);
    $dst_r = ImageCreateTrueColor( $targ_w, $targ_h );

    imagecopyresampled($dst_r,$img_r,0,0,$_POST['x'],$_POST['y'],
    $targ_w,$targ_h,$_POST['w'],$_POST['h']);

    header('Content-type: image/jpeg');
    imagejpeg($dst_r,null,$jpeg_quality);

Nor in here, or anywhere else, i see how to define the destination image path and filename.
I want to keep the original one in the temp folder and create the resized one in the parent folder.

Can someone help me please?

score 1 · Accepted Answer · answered Mar 05 '11 at 22:53

1

Nor in here, or anywhere else, i see how to define the destination image path and filename.

You'll find the manual page for imagejpeg() enlightening -- the second argument, which is null in your example code, is the destination file name.

I want to keep the original one in the temp folder and create the resized one in the parent folder.

Just be aware that the copy in the temporary directory may disappear once the script terminates.

answered Mar 05 '11 at 22:53

Charles

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you are absolutely right, i was only looking in the docs for imagecopyresampled, and i was looking for a function like 'imagesave' or something. Thank you – André Alçada Padez Mar 05 '11 at 23:02

imagecopyresampled in php -> destination file

1 Answers1