How to print a arrayline in seperate line in a TEXT FILE

Question

I have to print a Array List in a text file. I need a output in separate line but I got in same line.

Example: My expected output in text file: bat ball print my actual output is : [bat,ball,print]

my console it print line by line anyone help me to out of this issue thank you

Can you please share the code you used to print that array to the file ? — dWinder, Aug 07 '18 at 05:56
@Syed here we appreciate others help and work by up voting and accepting the solution that worked for you. It should not be like getting your answer and running away. Should always appreciate others taking their time out to help you. — IllegalSkillsException, Aug 08 '18 at 04:59

score 2 · Accepted Answer · answered Aug 07 '18 at 06:21

It would be helpful if you could give your code. But here is the code assuming strings are in ArrayList

import java.io.BufferedWriter;
import java.io.FileWriter;
import java.util.ArrayList;

public class TestJava{
    public static void main(String[] args){
        ArrayList<String> values = new ArrayList<>();
        values.add("bat");
        values.add("ball");
        values.add("print");
        BufferedWriter wr = null;
        try {
            wr = new BufferedWriter(new FileWriter("output.txt"));
            for (String var : values) {
                wr.write(var);
                wr.newLine();
            }
            wr.close();

        } catch (Exception e) {
            //TODO: handle exception
        }

    }
}

Atul Sharma · Answer 2 · 2018-08-07T06:04:29.627

You can use fout.writeChars() everytime, you call this a new line will be printed. Just loop through your list and print one by one.

try{

DataOutputStream fout = new DataOutputStream(new BufferedOutputStream (new FileOutputStream("Lines.Txt")));
fout.writeChars("This is first line");
fout.writeChars("This is second line");
fout.close();

}
catch (Exception e){
  e.printStackTrace();
  System.out.println("Exception occured..");
}

score 0 · Answer 3 · answered Aug 07 '18 at 06:00

I hope this sample code is working.

List<String> sample = new ArrayList<>();
    sample.add("sample");
    sample.add("sample1");
    sample.add("sample2");
    sample.add("sample3");
    ;
    System.out.println(sample.stream().map(Object::toString)
            .collect(Collectors.joining("\n")));

score 0 · Answer 4 · edited Nov 02 '18 at 19:01

You can do something like:

public static void main(String[] args) {
String data= null;
List<String> test = new ArrayList<>();
test.add("test");
test.add("test1");
test.add("test2");
test.add("test3");

    try {
        BufferedWriter bw = new BufferedWriter(new FileWriter(FILENAME));
        for(String testList : test) {
        data = testList;

        bw.write(data);
        bw.newLine();
        }

    } catch (IOException e) {

        e.printStackTrace();

    } finally {
    bw.close();
    }

}

score 0 · Answer 5 · answered Aug 07 '18 at 06:25

Here is a working solution to what I understood your problem was:

        List<String> sample = new ArrayList<>();
        sample.add("foo");
        sample.add("bar");
        sample.add("bizz");
        sample.add("bazz");

        BufferedWriter writer = new BufferedWriter(new FileWriter("out.txt"));
        sample.stream().forEach(s -> {
            System.out.println(s);
            try {
                writer.write(s + '\n');
            } catch (IOException e) {
                e.printStackTrace();
            }
        });
        writer.close();

First it adds some strings to the list. The stream and forEach are the functional way to do iteration nowadays. Then you write to file.

How to print a arrayline in seperate line in a TEXT FILE

5 Answers5