Android navigation component open url

Question

I have simple code that opens URL in a browser:

startActivity(Intent(
    Intent.ACTION_VIEW, Uri.parse(resources.getString(R.string.application_url))
))

How can I convert this to the navigation component item?

Do I need to build custom navigator for this, or navigation component has something built in for such case?

Answer 1

I figured it out, for this simple case custom navigator is not needed all you need is to create navigation endpoint:

<activity
    android:id="@+id/navigation_endpoint_id"
    app:action="android.intent.action.VIEW"
    app:data="@string/application_url"/>

Answer 2

For Dynamic Uri, we can pass the data like this:

<activity
    android:id="@+id/whatsappRedirectionActivity"
    app:action="android.intent.action.VIEW"
    app:dataPattern="https://wa.me/{number}">
    <argument
         android:name="number"
         app:argType="string" />
</activity>

This needs to include to navigation graph where you want to redirection. Using this we can use safeargs actions as well.

Answer 3

If you are using Navigation drawer, you can set this programmatically like this. This way you can set custom function for a particular navigation item without losing navigation graph advantages

navigationView.setNavigationItemSelectedListener {item->
                drawerLayout.closeDrawer(GravityCompat.START)
                when(item.itemId){
                    R.id.navigation_rate -> {
                        startActivity(Intent(
                                Intent.ACTION_VIEW, Uri.parse(resources.getString(R.string.app_playstore_url))
                        ))
                        return@setNavigationItemSelectedListener true
                    }
                    else  -> NavigationUI.onNavDestinationSelected(item, navController)
                }
            }