Every session data passed into the socket is broadcasted to all users since every session subscribes to the UnicastProcessor eventPublisher.
How can I send by event data to a single session id and not to all of them?
@Override
public Mono<Void> handle(WebSocketSession session) {
WebSocketMessageSubscriber subscriber = new WebSocketMessageSubscriber(eventPublisher);
session.receive()
.map(WebSocketMessage::getPayloadAsText)
.map(this::toEvent)
.subscribe(subscriber::onNext, subscriber::onError, subscriber::onComplete);
return session.send(outputEvents.map(session::textMessage));
}
My use-case requires me to include both options for broadcasting any changed state with any client to all sockets connected plus the abillity to send response to a specific client (sessionId) that send a request within a specific event
or should It be routed to 2 different handlers from the same websocket path? note that from javascript
new WebSocket(url/path) creates a socket connection
there is no way to change the path without creating or instantiating a new WebSocket object which is not wanted. I'm not interested in creating for every browser client 2 sockets... so my goal is to base the server connection via 1 single websocket path
@Bean
public HandlerMapping webSocketMapping(UnicastProcessor<Event> eventPublisher, Flux<Event> events) {
Map<String, Object> map = new HashMap<>();
map.put("/websocket/chat", new ChatSocketHandler(eventPublisher, events));
SimpleUrlHandlerMapping simpleUrlHandlerMapping = new SimpleUrlHandlerMapping();
simpleUrlHandlerMapping.setUrlMap(map);
//Without the order things break :-/
simpleUrlHandlerMapping.setOrder(10);
return simpleUrlHandlerMapping;
}
if so would be glad to see an example of such solution
