In the following c-code, the function func1 decides which element of enumerate ENUM1 is given as input.
In the first call func1(ENUM_ELEMENT1); it works as expected but in the second and third calls the results are wrong (it is expected that the function prints ENUM_ELEMENT2 and ENUM_ELEMENT3 respectively but in both cases it prints ENUM_ELEMENT1)!
#include <stdio.h>
#include <stdint.h>
typedef enum
{
ENUM_ELEMENT1 = 0x0000001u,
ENUM_ELEMENT2 = 0x0000002u,
ENUM_ELEMENT3 = 0x0000004u,
ENUM_ELEMENT4 = 0x0000008u,
} ENUM1;
void func1( uint32_t inp )
{
if (0u != inp & ENUM_ELEMENT1)
{
printf("ENUM_ELEMENT1\n");
}
else if (0u != inp & ENUM_ELEMENT2)
{
printf("ENUM_ELEMENT2\n");
}
else if (0u != inp & ENUM_ELEMENT3)
{
printf("ENUM_ELEMENT3\n");
}
else if (0u != inp & ENUM_ELEMENT4)
{
printf("ENUM_ELEMENT4\n");
}
}
int main( void )
{
func1(ENUM_ELEMENT1); // prints ENUM_ELEMENT1 --> correct
func1(ENUM_ELEMENT2); // prints ENUM_ELEMENT1 --> wrong!
func1(ENUM_ELEMENT3); // prints ENUM_ELEMENT1 --> wrong!
getchar();
return 0;
}
