Scipy Euclidean distance between two points

Question

The below code for calculating the Euclidean distance between two points returns [[9.]] :

from scipy import spatial
d1 = [[11 , 3]]
d2 = [[2 , 3]]
print(spatial.distance.cdist(d1 , d2 ,  "euclidean"))

But the Euclidean distance between these two points is 3?

Has the Euclidean distance been implemented correctly?

Both points have the same y-coordinate of 3, so the line joining the points is horizontal, and its length is the difference between the x-coordinates, i.e. 11-2=9. — Mark Setchell, Jul 26 '18 at 07:49

score 2 · Accepted Answer · edited Jul 26 '18 at 08:04

2

The formula for Euclidean distance is the following: dist((x, y), (a, b)) = √((x - a)² + (y - b)²)

Which gives: = √((11 - 2)² + (3 - 3)²) = √(9)² = 9

edited Jul 26 '18 at 08:04

iacob

answered Jul 26 '18 at 07:56

Stef van der Zon

score 1 · Answer 2 · answered Jul 26 '18 at 07:45

1

The Distance is 9. Euclidian distance is root of sum of squared differences. So you have sqrt( (11-2)^2 ) which is sqrt( 9^2 ) which is 9

answered Jul 26 '18 at 07:45

Filip Skrinjar

2 Answers2