How to put String and Integer elements in LinkedHashMap with IntStream?

Question

I am new to LinkedHashMap and I want to put elements <String, Integer> in my Map with IntStream instead of filter.put("1", 1)... Is there any way to do it?

private Map<String, Integer> filter = new LinkedHashMap<>();

@PostConstruct
    public void init() throws IdNotFoundException {
        filter.put("1", 1);
        filter.put("2", 2);
        filter.put("3", 3);
        filter.put("4", 4);
        filter.put("5", 5);
        filter.put("6", 6);
        filter.put("7", 7);
        filter.put("8", 8);
        filter.put("9", 9);
        filter.put("10", 10);
        filter.put("All", -1);
    }

I have to put "1", 1 "2", 2 ... can I do it with lambda instead of using 11 lines of filter.put — , Jul 24 '18 at 13:24
if its always "1",1 why not use a simple loop? for(int i=0;i<10;i++){ filter.put(i,i); } — mayha, Jul 24 '18 at 13:25
Where should the initial data come from. The way you write it `"1", 1, "2", 2` sounds like an arbitrary array. But I'm really not sure on how you want to store the initial data? Or is that up to you? — Korashen, Jul 24 '18 at 13:26
Why would you use lambda for this? Just a regular loop would do just fine. — Ivar, Jul 24 '18 at 13:29

score 2 · Accepted Answer · answered Jul 24 '18 at 13:25

2

To do so, I suggest to use IntStream:

 Map<String, Integer> filter = new LinkedHashMap<>();
    IntStream.range(1, 11).forEach(integer -> filter.put(String.valueOf(integer), integer));
    filter.put("All", -1);

answered Jul 24 '18 at 13:25

Mustapha Belmokhtar

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How to put String and Integer elements in LinkedHashMap with IntStream?

1 Answers1