2

I have the following setup of my Flask application:

├── app
│   ├── __init__.py
│   └── routes.py
├── application.py
└── zappa_settings.json

application.py:

import os
from app import config_app


if __name__ == "__main__":
    application = config_app(os.environ, __name__)
    application.run(threaded=True)

app/__init__.py:

from flask import Flask

def config_app(config, name=__name__):
    app = Flask(__name__)
    app.config.from_mapping(config)
    ...
    return app

Now I'm trying to deploy the application with zappa to AWS. When running zappa init it prompts for an app_function, however I'm not entirely sure what to set it to. So far I've tried 

"app_function": "application.application"

Which returns a 502 error at the end.

Running zappa tail:

Traceback (most recent call last):
  File "/var/task/handler.py", line 567, in lambda_handler
  return LambdaHandler.lambda_handler(event, context)
  File "/var/task/handler.py", line 237, in lambda_handler
  handler = cls()
  File "/var/task/handler.py", line 132, in __init__
  wsgi_app_function = getattr(self.app_module, self.settings.APP_FUNCTION)
AttributeError: module 'application' has no attribute 'application'
wasp256
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1 Answers1

0

Apparently this is the right format of the application.py:

application = config_app(os.environ, __name__)

if __name__ == "__main__":
     application.run(threaded=True)
wasp256
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