TypeError: hola() takes 0 positional arguments but 1 was given

Question

This a simply code that I trying to access to a method in a class from another method in the same class but it is given me that error any help?

class menu:
    def __init__(self,a,b):
        self.a=a
        self.b=b

    def suma(self):
        x=self.a+self.b
        print(x)

    def hola(): 
        menu.suma()


menu=menu(1,2)
menu.hola()

change `def hola(): menu.suma()` to `def hola(self): self.suma()` — eyllanesc, Jul 22 '18 at 00:47
@LeonardoRadilloescobar the answer that is marked as incorrect works but luckily, it is not the correct one. — eyllanesc, Jul 22 '18 at 01:03

score 0 · Accepted Answer · answered Jul 22 '18 at 00:45

0

How to avoid explicit 'self' in Python?

You need an explicit self in python. The self argument is always passed in.

class menu:
    def __init__(self,a,b):
        self.a=a
        self.b=b

    def suma(self):
        x=self.a+self.b
        print(x)

    def hola(self): 
        menu.suma()


menu=menu(1,2)
menu.hola()

answered Jul 22 '18 at 00:45

jshamble

391
2
14

Does your code work ?, have you tried it? – eyllanesc Jul 22 '18 at 00:48

TypeError: hola() takes 0 positional arguments but 1 was given

1 Answers1