SPARQL SKOS:broaderTransitive

Question

I'm using Fuseki server to update and query my ontology , I need to use SKOS concept to create Hierarchical tag relation , for exemple i Hava this Hierarchical relation

A------------>B--------------------->C A in relation with B and B in relation with C so A is in relation with C so I use this SPARQL query to add those relations :

 PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
 PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#>
 PREFIX skos: <http://www.w3.org/2004/02/skos/core#>
 INSERT DATA  {
 <A> skos:broaderTransitive <B>.
 <B> skos:narrowerTransitive <A> .

}

And

  PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
  PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#>
  PREFIX skos: <http://www.w3.org/2004/02/skos/core#>
  INSERT DATA  {
  <B> skos:broaderTransitive <C>.
  <C> skos:narrowerTransitive <B> .

  }

and when i need to get the result i use :

    PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
    PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#>
    PREFIX skos: <http://www.w3.org/2004/02/skos/core#>
    select * where { <A> skos:broaderTransitive ?x}

And i get only B and i don't get B & C

i don't know if i need to add something because i have a problem with inference ... I don't know that i need to do, someone have an idea ? thanks

How should Fuseki know that the relation is transitive?! It's just plain SPARQL that you're using - even a standard reasoning profile won't help here. Either you add a custom rule set using the generic rule reasoner of Jena or even simpler, use SPARQL 1.1 property paths: `select * where { skos:broaderTransitive* ?x}` — UninformedUser, Jul 19 '18 at 19:01
AKSW thanks ;) select * where { skos:broaderTransitive+ ?x} is what i need . — mell.la, Jul 19 '18 at 19:41

SPARQL SKOS:broaderTransitive

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