How to send error message to slack using webhook and Python?

Question

I have several Python functions. In case of any error I want to send the error message to slack. For this I have added below line in except block of my code-

    except Exception as ex:
     msg = 'There is a problem with csv generation due to: {}'.format(ex)
     logger.info(msg)
     send_message("web_hook_url",msg)

My send_message() looks like below-

def send_message(webhook_url, message):
 response = requests.post(
     webhook_url, data=json.dumps(message),
     headers={'Content-Type': 'application/json'}
 )
 if response.status_code != 200:
     raise ValueError(
         'Request to slack returned an error %s, the response is:\n%s'
         % (response.status_code, response.text)
     )

I saw the following link slack webhook post But I am confused here how to use my send_message() in my except block of code?

Can anyone please help me how to achieve this?

score 3 · Accepted Answer · answered Jul 18 '18 at 08:51

3

The data in the request needs to be in the correct format, so..

logger.info(msg)
slackmsg = {"text": msg}
send_message(self, slackmsg)

answered Jul 18 '18 at 08:51

Zak

48
5

Thanks Zak! I am able to do it now :) – AnalyticsPy Jul 18 '18 at 08:55

Amir Gohar · Answer 2 · 2018-07-18T08:29:27.353

1

your payload must have a key named "text" in it.

def send_message(self, message):
    payload = {"text": message}
    try:
        return requests.post(self.url, data=json.dumps(payload), headers={'Content-Type': 'application/json'})
    except requests.exceptions.RequestException as e:
        print e.message
        return False

And to your question how to use it, you can format your message like this:

{
    "message": ex.message

}

Also take a look on this tool Sentry

edited Jul 18 '18 at 08:29

answered Jul 18 '18 at 08:21

Amir Gohar

58
6

Amir, what is the current_app here? Should I use logger.error(e) only? And my except block looks fine? – AnalyticsPy Jul 18 '18 at 08:24
sorry that was from my app, you can use simple python logger here to print it – Amir Gohar Jul 18 '18 at 08:33
please take a look on this `payload = {"text": message}`, you need to send payload in this form to slack webhook url – Amir Gohar Jul 18 '18 at 08:35
can you please edit my except block and share what should be modified there? – AnalyticsPy Jul 18 '18 at 08:45
Thanks Amir, it was really helpful! – AnalyticsPy Jul 18 '18 at 08:55

How to send error message to slack using webhook and Python?

2 Answers2