formatting numbers pattern using for loops

Question

   1  
  3 2
 6 5 4
10 9 8 7
10 9 8 7 
 6 5 4 
  3 2 
   1

userInput=5

for i in range(1,userInput+1):
    for s in range (userInput - i) :    # s is equivalent to to spaces
        print(" ", end="")
    for j in range(1,(i * 2) ):
        print(j, end="")            
    print()

for i in range(userInput-1, 0, -1):
    for s in range (userInput - i) :
        print(" ", end="")
    for j in range(1,(i * 2)):
        print(j, end="")           
    print()    


    1
   123
  12345
 1234567
123456789
 1234567
  12345
   123
    1

This is the output am getting

i am trying to get this format,but i am getting continuous number.Even the rows are in odd format .Any suggestions please

@user3483203 no...its actually contigious numbers in reversed pattern — arthur_curry, Jul 15 '18 at 05:26
Could you post what incorrect output you are receiving, for our convenience? — Dillon Davis, Jul 15 '18 at 05:26
@arthur_curry it would be pretty easy to adapt the code I linked to fit your requirements.. — user3483203, Jul 15 '18 at 05:30
Change `end=""` to `"end=" "` to fix your spacing issue, `range(1,(i * 2) )` to `range(i+1)`, and instead of printing `j`, print the next element from a generator. Probably something like `gen=iter(range(1,userInput*(userInput+1)/2+1)) ... next(gen)` — Dillon Davis, Jul 15 '18 at 05:37

score 0 · Answer 1 · answered Jul 15 '18 at 06:00

Here's a solution using list comprehensions and some string manipulation:

def tri(num):
    return num * (num + 1) // 2

def make_list(size, depth=1):
    shape = " " * (size - depth - 1)
    shape += " ".join((str(tri(depth) - x) for x in range(depth)))
    if depth == size:
        return []
    return make_list(size, depth + 1) + [shape]

def print_dia(size):
    dia = make_list(size)
    print("\n".join(dia[::-1]))
    print("\n".join(dia))

if __name__ == "__main__":
    print_dia(5)

I generate each line by using the overall size and the current line number to produce the correct indentation, starting value (a triangular number), and the number of values on that line. I then produce a list of lines, print the reversed list first, then the original list, separated by newlines.

its working..thank u so much – arthur_curry Jul 15 '18 at 06:27 — arthur_curry, Jul 15 '18 at 06:27

score -1 · Accepted Answer · answered Jul 15 '18 at 16:49

userInput=5    
temp=0

for i in range(1,userInput+1):
    temp+=i
    for s in range(0,userInput-i):
        print(" ",end="")    
    for j in range(i):        
        print(temp-j,end=" ")         
    print()
for j in range(userInput,0,-1):
    for s in range(userInput-j):
        print(" ",end="")
    for j in range(j):
        print(temp,end=" ")
        temp-=1
    print()

@arthur_curry...i just used for loops for desired output..i have used a temp variable to keep the count and added with i(each stage value).Printing the values in descending.

Hi...its too easy to understand..thank u so much – arthur_curry Jul 15 '18 at 16:57 — arthur_curry, Jul 15 '18 at 16:57

formatting numbers pattern using for loops

2 Answers2