how to run exe file and type arguments from python

Question

I have an executable external program that ask the name of the arguments file.

I am trying to program this action through python coding. How can it be done?

Yuval Keysar · Answer 1 · 2018-07-04T16:57:08.717

2

if you want to run exe file you can use:

import os
path = "exe-file-path.exe"
os.system("start " + path)

os library is built-in (both python 2,3)

edited Jul 04 '18 at 16:57

answered Jul 04 '18 at 16:54

Yuval Keysar

51
4

but how to input the argument? – jmparejaz Jul 04 '18 at 16:57
1

what do you mean? – Yuval Keysar Jul 04 '18 at 17:23
I mean, the software is asking to type another file that contains parameters, how do i set up that file name in python code – jmparejaz Jul 04 '18 at 20:00

score 0 · Answer 2 · answered Jul 15 '19 at 16:12

You must use sys and os module and here is sample code:

import sys
import os

if sys.argv[1] == "something":
    # Do something

Remember that sys.argv[0] is script itself and sys.argv[1] is first argument like example.py first_argument. If first argument can be other things [and other arguments if available], just add more variants. If it has more arguments, just add elif sys.argv[%next number%] == "something": # Do something. And also replace # Do something with valid command to do when that argument is choosen.

Don't forget that this must be runned from CMD [On Windows] or Bash [On Unix, also called Linux systems]! — UltraStudioLTD, Jul 15 '19 at 16:13

how to run exe file and type arguments from python

2 Answers2