Jenkins Slave Java path on MacOS

Question

Here is my jenkins slave configure configure_img

Here is the process result result_img

Is there anybody can help me to solve it? Thank you very much

Welcome to StackOverflow. Please don't post text output as image, copy the raw text next time, please. — StephenKing, Jul 04 '18 at 04:51
You will also have more success if you switch your application to english, so that everybody can understand the outputs. — StephenKing, Jul 04 '18 at 04:52

score 1 · Answer 1 · answered Jul 04 '18 at 04:54

Your configuration setting for the Java path (?) is incorrect (you supplied /usr/bin). You see it in the output that it tries to launch a command called /usr/bin, which is not an executable file. That's why you get permission denied for it.

An example for a correct path would be /usr/bin/java, or wherever your java executable is located.

score 0 · Answer 2 · answered Jul 04 '18 at 08:39

Thanks for posting detailed error and configuration.

You need to fix the Java executable path in your slave configuration.

1) You can find your Java executable from below command

$ which java

2) Test if java is properly configured from terminal:

$ java -version You should see something like

java version "1.8.0_131" Java(TM) SE Runtime Environment (build 1.8.0_131-b11) Java HotSpot(TM) 64-Bit Server VM (build 25.131-b11, mixed mode)

Jenkins Slave Java path on MacOS

2 Answers2