Can Array.prototype.includes() search for an Array?

Asked Jul 03 '18 at 11:05

Active Jul 03 '18 at 11:21

Viewed 39 times

Consider the following code:

let a = [
  ["10.237.77.82", "10.237.79.255"],
  ["10.237.78.2", "230.0.0.1"],
  ["10.237.78.2", "10.237.79.255"]
]
console.log(a.includes(["10.237.77.82", "10.237.79.255"]))

I was expecting the includes() to find the Array ["10.237.77.82", "10.237.79.255"], why isn't it the case?

Array.prototype.includes() documentation does not seem to suggest specific elements which are "foundable" (although the examples are only with an Integer or a String)

asked Jul 03 '18 at 11:05

WoJ

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1

`console.log([] === [])` --> false – baao Jul 03 '18 at 11:09
1

Looks like it works only with primitives – P.S. Jul 03 '18 at 11:11
1

It does only work with primitives. There not a single example that uses arrays. – Alex Jul 03 '18 at 11:12
You can just convert each element to string. console.log(a.join("").includes("10.237.77.82", "10.237.79.255")); – Joven28 Jul 03 '18 at 11:16
`includes` will work work on objects/array, if two objects refer to the same Object. – bastos.sergio Jul 03 '18 at 11:21
Here's my workaround: [`JSFiddle`](https://jsfiddle.net/j9xvhnum/36/) – Alex Jul 03 '18 at 11:28

Can Array.prototype.includes() search for an Array?

0 Answers0