Swift Mapping Data to [String: Any]

Question

I would like to convert a Data type to [String: Any], but the JSONSerialization tells me:

Cannot force unwrap value of non-optional type 'Data'

var json: [String: Any]
            do{
                let jsonEncoder = JSONEncoder()
                let encodedJson = try jsonEncoder.encode(message)
                json = try JSONSerialization.data(withJSONObject: encodedJson!, options: []) as? [String : Any]
            } catch {
                log.error(error.localizedDescription)
            }
return .requestParameters(parameters: json, encoding: JSONEncoding.default)

If I remove the '!' from encodedJson, then the Message occure:

Value of optional type '[String : Any]?' not unwrapped; did you mean to use '!' or '?'?

If I remove the '?' from any?, then I use json without initializing it, of course

Didn't know how to fix this (new swift coder)

Hope this is not a stupid question

please share some more code, especially what is the value of message variable? — Nasir, Jul 02 '18 at 08:10

vadian · Answer 1 · 2018-07-02T08:22:38.097

You are using the wrong API, data(withJSONObject creates Data from a array or dictionary

You need the other way round. To resolve the issues remove the exclamation mark after encodedJson

json = try JSONSerialization.jsonObject(with: encodedJson) as? [String : Any]

and declare json as optional

var json: [String: Any]?

Or – if the JSON is guaranteed to be always a dictionary – force unwrap the object

json = try JSONSerialization.jsonObject(with: encodedJson) as! [String : Any]

score 1 · Accepted Answer · answered Jul 02 '18 at 08:10

1

There is no need for this as you already have the data in encodedJson

json = try JSONSerialization.data(withJSONObject: encodedJson!, options: []) as? [String : Any]

as withJSONObject expects an object not Data , also casting it to [String:Any] will fail

answered Jul 02 '18 at 08:10

Shehata Gamal

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okay thanks :) , but how can I convert my encodedJson to [String: Any]? – rocklyve Jul 02 '18 at 08:12

Swift Mapping Data to [String: Any]

2 Answers2