How to drop string after certain point in all elements of list?

Question

I have a large string stored in a list. I only need to extract the URL and dump the rest of the string. How would I do this? The bold is all I need and for every element in the list, the ? is the cut off where I want to capture the URL. I am not sure if this will the 'u' disappear as well.

lst =[u'https://images.com/candles.jpg?asdkfasdkfihawklwie']

Just want to emphasis that I want to drop everything after the question mark including the question mark itself for every element in the list. Only need the URL.

Thank you in advance.

jezrael · Accepted Answer · 2018-06-24T21:26:47.357

0

Use split with list comprehension:

L = [x.split('?', 1)[0] for x in lst]

As @Martijn Pieters commented faster is use partition:

L = [x.partition('?')[0] for x in lst]

edited Jun 24 '18 at 21:26

answered Jun 24 '18 at 21:21

jezrael

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No, use `str.partition()`, which is faster for a single split. Or at the very least limit the number of splits. Or, in this case, *use a URL parser* to remove a URL component. – Martijn Pieters Jun 24 '18 at 21:22
@MartijnPieters where would I insert the 'str.partition()' – RustyShackleford Jun 24 '18 at 21:25

How to drop string after certain point in all elements of list?

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