Sort dictionary with multiple values based on sum

Asked Jun 20 '18 at 15:38

Active Jun 20 '18 at 15:43

Viewed 211 times

I have a dictionary like this

({'Apple': [1,5,3,1,6], 'Banana': [9,12,4,5,1]})

and I want to create a sorted list out of it where sorting is based on the sum of the values.

The following code does not work though:

sorted_list = sorted(mylist.items(), key=lambda x: sum(x[1]), reverse=True)

It always says TypeError: 'int' object is not callable.

If I leave out the sum function it works, but sorting is based on the FIRST value in the list. If I try something like key=lambda x: (x[1][0]+x[1][1]) it sums up the first two values in the list and sorts based on the result. So sorting based on the sum DOES WORK, but not with the sum function but only by manually adding the elements. Why though?

asked Jun 20 '18 at 15:38

8

Somewhere earlier in your program, you assigned `sum` to be an int, shadowing the built-in. Or at least that's my guess. – miradulo Jun 20 '18 at 15:40
2

I can't reproduce this, your code works for me. – Patrick Haugh Jun 20 '18 at 15:40
Thanks. I feel dumb because I didn't notice I already had the variable `sum` in my code. I renamed it and it works. – Jun 20 '18 at 15:45

Sort dictionary with multiple values based on sum

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