Using Angular 6, I want to concat Firstname and Lastname in bindLabel inside ng-select tag ?
Here is my html : ng-select [items]="persons" bindLabel="LastName" bindValue="Id" [(ngModel)]="selectedItem" placeholder="person"
Any idea ? bindLabel="LastName + ' ' +FirstName" => doesn't work bindLabel="person.Name as (person.LastName + ' ' person.FirstName) for person in persons" => doesn't work
A better way for display the full name is:
<ng-select required [items]="buddies" bindLabel="firstName" #buddiesInput="ngModel" [(ngModel)]="userSelect" name="userSelect" >
<ng-template ng-label-tmp let-item="item">
{{item.firstName}} {{item.lastName}}
</ng-template>
<ng-template ng-option-tmp let-item="item" let-search="searchTerm">
{{item.firstName}} {{item.lastName}}
</ng-template>
</ng-select>
Pretty old question but I will still answer. I happened to catch this question as I am also looking for the same solution.
Not maybe the best practice or there might be much better solution but I just created a map for my array so I could create a new field for full_name.
See code below if this could help you out.
template:
<ng-select
[(ngModel)]="_selected_user"
[items]="_all_users"
placeholder="Select User"
bindLabel="full_name"
bindValue="id"
>
<ng-template ng-option-tmp let-item="item" let-search="searchTerm">
<div><span></span><span [ngOptionHighlight]="search">{{item.full_name }}</span></div>
<small>User ID: <b>{{item.user_id}}</b> </small>
</ng-template>
</ng-select>
component:
users.map(
(user: any) => {
user.full_name = user.last_name + ', ' + member.first_name + ' ' + member.middle_name
return member;
}
)
This one will enable searching via first_name or last_name or middle_name or altogether in one search key.
