Why does C's strcpy fail with doubly indexed arrays?

Question

The following code seems to segfault and I cannot figure out why.

#include <string.h>

static char src[] = "aaa";

int main()
{
   char* target[2] = {"cccc","bbbbbbbbbb"};
   strcpy(target[1],src);
   return 0;
}

Answer 1

Because target[1] is a pointer to "bbbbbbbbbb" and you are not allowed to modify string constants. It's undefined behaviour.

It's no different to:

char *x = "bbb";
x[0] = 'a';

I think you may be confusing it with:

char x[] = "bbb";
x[0] = 'a';

which is valid since it creates an array that you are allowed to modify. But what yours gives you:

char* target[2] = {"cccc","bbbbbbbbbb"};

is an array of pointers, all of which point to non-modifiable memory.

If you were to try:

char t0[] = "cccc";
char t1[] = "bbbbbbbbbb";
char* target[2] = {t0, t1};
strcpy(target[1],src);

you would find that it works since target[1] now points to t1, which is modifiable.