How to replace string with an array() in php

Question

I have a text like this,

$string = "I have some fruits like [name], [another_name] and [one_another_name]";

And an array like this,

$fruits_array = array("Banana", "Apple", "Orange");

Now, how can I replace the texts between braces by following array?

I want a result like this,

I have some fruits like Banana, Apple and Orange.

Please provide the actual solution.

Thanks in advance.

@tanmoy-dutta - possible DUPLICATE. check https://stackoverflow.com/questions/8586141/implode-array-with-and-add-and-before-last-item#answer-25057951 — Jaydp, Jun 07 '18 at 06:11
Thanks @Sudhir Ojha for your suggestion. But sorry to say that I didn't found in that post what actually I need. — Teenager, Jun 07 '18 at 06:25

Rendi Wahyudi Muliawan · Answer 1 · 2018-06-07T06:58:24.803

3

Try this

$string = "I have some fruits like [name], [another_name] and [one_another_name]";
$fruits_array = array("Banana", "Apple", "Orange");

foreach($fruits_array as $replace)
{
    $string = preg_replace('/\[.*?\]/i', $replace, $string, 1);
}

echo $string;

edited Jun 07 '18 at 06:58

answered Jun 07 '18 at 06:12

Rendi Wahyudi Muliawan

284
1
9

sorry it was by mistake – PPL Jun 07 '18 at 06:13
Elegant approch base on regex. Nice pruposal – Yanis-git Jun 07 '18 at 06:14
If we give fullstop `.` at the end, output is getting weird. – Sambhaji Katrajkar Jun 07 '18 at 06:17
Thanks you all. But sorry to say that it's not working. Do you have any alternative idea? – Teenager Jun 07 '18 at 06:33
Do you have different code? If you have then post it, I already tried my answer and its successful – Rendi Wahyudi Muliawan Jun 07 '18 at 06:47
Please provide the solution if my string will be like this, $string = "I have some fruits like [name], [another_name] and [one_another_name]"; As I have edited my post. – Teenager Jun 07 '18 at 06:55

score 1 · Answer 2 · answered Jun 07 '18 at 06:19

<?php

$string = "I have some fruits like [name], [name] and [name]";

$fruits_array = array("Banana", "Apple", "Orange");

foreach ($fruits_array as $key => $value) {
  $string = preg_replace('[name]', $value, $string, 1);
}
$string = str_replace('[', '', $string);
$string = str_replace(']', '', $string);
echo $string;

score 0 · Answer 3 · answered Jun 07 '18 at 06:04

0

Implode the array by comma with space. Try like this :

$fruits_array = array("Banana", "Apple", "Orange");

echo 'I have some fruits like '.implode(', ',$fruits_array).'.';

answered Jun 07 '18 at 06:04

Sambhaji Katrajkar

409
2
10

score 0 · Answer 4 · answered Jun 07 '18 at 06:20

Try this...

$string = "I have some fruits like [name], [name] and [name]";
$arr = explode('[name]',$string);
$fruits_array = array("Banana", "Apple", "Orange");

$newText = '';
for($i = 0; $i < count($arr); $i++){
   $newText .= $arr[$i] . $fruits_array[$i];
}

echo $newText;

The fourth bird · Accepted Answer · 2018-06-07T08:36:20.600

0

You might also use preg_replace_callback with a regex \[[^]]+\] to match an opening [, then match not a ] using a negated character class and then match ].

In the callback use array_shift to shift an element off the beginning of the array and use that as the replacement.

$string = "I have some fruits like [name], [another_name] and [one_another_name]";
$fruits_array = array("Banana", "Apple", "Orange");

$string = preg_replace_callback(
    '/\[[^]]+\]/',
    function ($matches) use (&$fruits_array) {
        return array_shift($fruits_array);
    },
    $string
);

echo $string;

Demo

edited Jun 07 '18 at 08:36

answered Jun 07 '18 at 06:27

The fourth bird

154,723
16
55
70

@TanmoyDutta I have changed my answer to `preg_replace_callback` because the previous will not work when there already is `%s` present in the string. – The fourth bird Jun 07 '18 at 08:39
Thanks @TheFourthBird – Teenager Jun 07 '18 at 09:53

How to replace string with an array() in php

5 Answers5